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Proof step 18 from proof bytes2bytes-fix (previous step)

¬ i2b(b2i(by)) ≠ i2b(0), b2i(by) = 0, 0 ≤ b2i(by0), ∀ bytes0. # bytes0 < #(by + by0 + bytes) → true → bytes0 = [] ∨ fix(# bytes0, int2bytes(bytes2int(bytes0))) = bytes0 ⊦ fix(2 + # bytes, int2bytes(bytes2int(by ' + by0 ' + bytes))) = by ' + by0 ' + bytes

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 19:
0 ≤ b2i(by0), ∀ bytes0. # bytes0 < #(i2b(0) + by0 + bytes) → true → bytes0 = [] ∨ fix(# bytes0, int2bytes(bytes2int(bytes0))) = bytes0 ⊦ fix(2 + # bytes, int2bytes(bytes2int(i2b(0) ' + by0 ' + bytes))) = i2b(0) ' + by0 ' + bytes

Rule argument

Additional information

Used simplifier rules: ⊦ b2i(i2b(0)) = 0;% ⊦ i2b(b2i(by)) = by;