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Proof step 31 from proof bytes2bytes-fix (previous step)

1 < #(by ' + bytes1) ∧ b2i((by ' + bytes1).first) = 0 ∧ b2i((by ' + bytes1).rest.first) < 0, b2i(by) = 0, ∀ bytes0. # bytes0 < #(by + bytes1) → true → bytes0 = [] ∨ fix(# bytes0, int2bytes(bytes2int(bytes0))) = bytes0 ⊦ fix(1 + # bytes1, by ' + bytes1) = by ' + bytes1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 32:
b2i(by) = 0, b2i(bytes1.first) < 0, ∀ bytes0. # bytes0 < #(by + bytes1) → true → bytes0 = [] ∨ fix(# bytes0, int2bytes(bytes2int(bytes0))) = bytes0 ⊦ fix(1 + # bytes1, by ' + bytes1) = by ' + bytes1, bytes1 = []

Rule argument

Additional information

Used simplifier rules: ⊦ j < i ∧ i ≤ 0 → j < 0; (forward)% ⊦ (by ' + bytes).rest = bytes;% ⊦ # bytes = 0 ↔ bytes = [];% ⊦ m + n = 1 ↔ m = 0 ∧ n = 1 ∨ n = 0 ∧ m = 1;% ⊦ m + n = n + m;% ⊦ (m + n0) + n1 = m + n0 + n1;% ⊦ m + 1 ≠ 0;% ⊦ 1 < m ↔ ¬(m = 0 ∨ m = 1);% ⊦ # by ' = 0 +1;% ⊦ #(bytes + bytes0) = # bytes + # bytes0;% ⊦ (bytes + bytes0) + bytes1 = bytes + bytes0 + bytes1;% ⊦ (by ' + bytes).first = by;