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Proof step 6 from proof bytes2bytes-fix (previous step)

¬(bytes ≠ [] ∧ b2i(bytes.first) ≠ 0 ∧ b2i(bytes.first) ≠ ~1), ∀ bytes0. # bytes0 < # bytes → true → bytes0 = [] ∨ fix(# bytes0, int2bytes(bytes2int(bytes0))) = bytes0 ⊦ fix(# bytes, int2bytes(bytes2int(bytes))) = bytes, bytes = []

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 7:
∀ bytes0. # bytes0 < # bytes → true → bytes0 = [] ∨ fix(# bytes0, int2bytes(bytes2int(bytes0))) = bytes0 ⊦ fix(# bytes, int2bytes(bytes2int(bytes))) = bytes, bytes = [], b2i(bytes.first) ≠ 0 ∧ b2i(bytes.first) ≠ ~1

Proof step 6 from proof bytes2bytes-fix (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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