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Proof step 9 from proof bytes2bytes-fix (previous step)

∀ bytes0. # bytes0 < #(by + bytes1) → true → bytes0 = [] ∨ fix(# bytes0, int2bytes(bytes2int(bytes0))) = bytes0 ⊦ fix(1 + # bytes1, int2bytes(bytes2int(by ' + bytes1))) = by ' + bytes1, b2i(by) ≠ 0 ∧ b2i(by) ≠ ~1

User applied rule case distinction

And obtained the following new goals

Rule argument

pos: right 2

Additional information