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Proof step 2 from proof bytes2bytes-identity (previous step)

# bytes = # int2bytes(bytes2int(bytes)) ⊦ int2bytes(bytes2int(bytes)) = bytes

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
bytes ≠ [], b2i(bytes.first) ≠ 0, b2i(bytes.first) ≠ ~1 ⊦ int2bytes(bytes2int(bytes)) = bytes
Proof step 4:
¬(bytes ≠ [] ∧ b2i(bytes.first) ≠ 0 ∧ b2i(bytes.first) ≠ ~1), # bytes = # int2bytes(bytes2int(bytes)) ⊦ int2bytes(bytes2int(bytes)) = bytes

Rule argument

name: bytes2bytes-other rotate: F subst: [bytes] → [bytes]

Additional information

Used terms: bytes