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Proof step 22 from proof bytes2bytes-identity (previous step)

1 + # bytes0 = # int2bytes(bytes2int(by ' + bytes0)), b2i(by) = 0 ⊦ int2bytes(bytes2int(by ' + bytes0)) = by ' + bytes0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 23:
1 < # bytes, b2i(bytes.first) = 0, b2i(bytes.rest.first) < 0 ⊦ int2bytes(bytes2int(bytes)) = bytes
Proof step 24:
¬(1 < #(by ' + bytes0) ∧ b2i((by ' + bytes0).first) = 0 ∧ b2i((by ' + bytes0).rest.first) < 0), 1 + # bytes0 = # int2bytes(bytes2int(by ' + bytes0)), b2i(by) = 0 ⊦ int2bytes(bytes2int(by ' + bytes0)) = by ' + bytes0

Rule argument

name: bytes2bytes-zero rotate: F subst: [bytes] → [by ' + bytes0]

Additional information

Used terms: by ' + bytes0