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Proof step 27 from proof bytes2bytes-identity (previous step)

b2i(by) = 0, 2 + # bytes = # int2bytes(bytes2int(by ' + by0 ' + bytes)), 0 ≤ b2i(by0) ⊦ int2bytes(bytes2int(by ' + by0 ' + bytes)) = by ' + by0 ' + bytes

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 28:
⊦ i2b(i) ≠ i2b(j) → i ≠ j
Proof step 29:
¬ i2b(b2i(by)) ≠ i2b(0), b2i(by) = 0, 2 + # bytes = # int2bytes(bytes2int(by ' + by0 ' + bytes)), 0 ≤ b2i(by0) ⊦ int2bytes(bytes2int(by ' + by0 ' + bytes)) = by ' + by0 ' + bytes

Rule argument

seq: ⊦ i2b(i) ≠ i2b(j) → i ≠ j subst: [j, i] → [0, b2i(by)] rotate: F spec: byte inst: name: i2b-noteq

Additional information

Used terms: 0, b2i(by)