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Proof step 6 from proof bytes2bytes-identity (previous step)

bytes = by + bytes0, # bytes = # int2bytes(bytes2int(bytes)) ⊦ int2bytes(bytes2int(bytes)) = bytes, bytes = [], b2i(by) ≠ ~1 ∧ b2i(by) ≠ 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 7:
1 + # bytes0 = # int2bytes(bytes2int(by ' + bytes0)) ⊦ int2bytes(bytes2int(by ' + bytes0)) = by ' + bytes0, b2i(by) ≠ ~1 ∧ b2i(by) ≠ 0

Rule argument

Additional information

Used simplifier rules: ⊦ by ' + bytes ≠ [];% ⊦ (bytes + bytes0) + bytes1 = bytes + bytes0 + bytes1;% ⊦ # by ' = 0 +1;% ⊦ #(bytes + bytes0) = # bytes + # bytes0;% ⊦ by + bytes = by ' + bytes;