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Proof step 9 from proof bytes2bytes-identity (previous step)

1 + # bytes0 = # int2bytes(bytes2int(by ' + bytes0)), b2i(by) = ~1 ⊦ int2bytes(bytes2int(by ' + bytes0)) = by ' + bytes0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 10:
1 < # bytes, b2i(bytes.first) = ~1, 0 ≤ b2i(bytes.rest.first) ⊦ int2bytes(bytes2int(bytes)) = bytes
Proof step 11:
¬(1 < #(by ' + bytes0) ∧ b2i((by ' + bytes0).first) = ~1 ∧ 0 ≤ b2i((by ' + bytes0).rest.first)), 1 + # bytes0 = # int2bytes(bytes2int(by ' + bytes0)), b2i(by) = ~1 ⊦ int2bytes(bytes2int(by ' + bytes0)) = by ' + bytes0

Rule argument

name: bytes2bytes-mone rotate: F subst: [bytes] → [by ' + bytes0]

Additional information

Used terms: by ' + bytes0