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Proof step 1 from proof bytes2bytes-length (conclusion)

⊦ bytes ≠ [] → # int2bytes(bytes2int(bytes)) ≤ # bytes

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
# bytes < # int2bytes(bytes2int(bytes)) ⊦ bytes = []

Rule argument

Additional information

Used simplifier rules: int2bytes-empty: ⊦ int2bytes(i) ≠ [];% ⊦ # bytes = 0 ↔ bytes = [];% ⊦ m < n → n ≠ 0; (forward)% ⊦ ¬ m ≤ n ↔ n < m;