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Proof step 18 from proof bytes2bytes-length (previous step)

0 ≤ b2i(by), 2 + # bytes < # int2bytes(bytes2int(i2b(0) ' + by ' + bytes)), ∀ bytes0. # bytes0 < #(i2b(0) + by + bytes) → # bytes0 < # int2bytes(bytes2int(bytes0)) → bytes0 = [] ⊦

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 19:
⊦ 0 ≤ b2i(by) → bytes2int(i2b(0) ' + by ' + bytes) = bytes2int(by ' + bytes)
Proof step 20:
0 ≤ b2i(by), 0 ≤ b2i(by), 2 + # bytes < # int2bytes(bytes2int(by ' + bytes)), ∀ bytes0. # bytes0 < #(i2b(0) + by + bytes) → # bytes0 < # int2bytes(bytes2int(bytes0)) → bytes0 = [] ⊦

Rule argument

name: bytes2int-zero-04 rotate: F subst: [bytes, by] → [bytes, by]

Additional information

Used terms: bytes, by