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Proof step 9 from proof bytes2bytes-length (previous step)

1 + # bytes1 < # int2bytes(bytes2int(by ' + bytes1)), ∀ bytes0. # bytes0 < #(by + bytes1) → # bytes0 < # int2bytes(bytes2int(bytes0)) → bytes0 = [] ⊦ b2i(by) ≠ 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 10:
b2i(by) = 0, 1 + # bytes1 < # int2bytes(bytes2int(by ' + bytes1)), ∀ bytes0. # bytes0 < #(by + bytes1) → # bytes0 < # int2bytes(bytes2int(bytes0)) → bytes0 = [] ⊦

Proof step 9 from proof bytes2bytes-length (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information