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Proof step 1 from proof bytes2bytes-mone (conclusion)

1 < # bytes, b2i(bytes.first) = ~1, 0 ≤ b2i(bytes.rest.first) ⊦ int2bytes(bytes2int(bytes)) = bytes

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 2:
⊦ bytes2int(bytes) = bits2int(bytes2bits(bytes))
Proof step 3:
1 < # bytes, b2i(bytes.first) = ~1, 0 ≤ b2i(bytes.rest.first) ⊦ int2bytes(bits2int(bytes2bits(bytes))) = bytes

Rule argument

name: bytes2int rotate: F subst: [bytes] → [bytes]

Additional information

Used terms: bytes