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Proof step 19 from proof bytes2bytes-mone (previous step)

b2i(by0) = ~1, 0 ≤ b2i(by), ∀ bytes1. # bytes1 < #((by0 + []) + by ') → b2i(bytes1.first) = ~1 ∧ 0 ≤ b2i(bytes1.rest.first) → bits2bytes(sgn(bytes2bits(bytes1))) = bytes1 ∨ # bytes1 = 1 ∨ bytes1 = [] ⊦ bits2bytes(sgn(byte2bits(by0) + byte2bits(by))) = by0 ' + by ', true ∈ byte2bits(by0) ∧ false ∈ byte2bits(by0)

User applied rule case distinction

And obtained the following new goals

Proof step 20:
b2i(by0) = ~1, 0 ≤ b2i(by), ∀ bytes1. # bytes1 < #((by0 + []) + by ') → b2i(bytes1.first) = ~1 ∧ 0 ≤ b2i(bytes1.rest.first) → bits2bytes(sgn(bytes2bits(bytes1))) = bytes1 ∨ # bytes1 = 1 ∨ bytes1 = [] ⊦ true ∈ byte2bits(by0), bits2bytes(sgn(byte2bits(by0) + byte2bits(by))) = by0 ' + by '
Proof step 22:
b2i(by0) = ~1, 0 ≤ b2i(by), ∀ bytes1. # bytes1 < #((by0 + []) + by ') → b2i(bytes1.first) = ~1 ∧ 0 ≤ b2i(bytes1.rest.first) → bits2bytes(sgn(bytes2bits(bytes1))) = bytes1 ∨ # bytes1 = 1 ∨ bytes1 = [] ⊦ false ∈ byte2bits(by0), bits2bytes(sgn(byte2bits(by0) + byte2bits(by))) = by0 ' + by '

Rule argument

pos: right 2

Proof step 19 from proof bytes2bytes-mone (previous step)

User applied rule case distinction

And obtained the following new goals

Rule argument

Additional information