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Proof step 31 from proof bytes2bytes-mone (previous step)

b2i(by0) = ~1, 0 ≤ b2i(by), ∀ bytes1. # bytes1 < #((by0 + []) + by ') → b2i(bytes1.first) = ~1 ∧ 0 ≤ b2i(bytes1.rest.first) → bits2bytes(sgn(bytes2bits(bytes1))) = bytes1 ∨ # bytes1 = 1 ∨ bytes1 = [] ⊦ bits2bytes(true ') + i2b(bits2int(lastn(8, true ' + byte2bits(by)))) ' = by0 ' + by '

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 32:
⊦ # bits ≤ 8 → bits2bytes(bits) = i2b(bits2int(bits)) '
Proof step 33:
# true ' ≤ 8, b2i(by0) = ~1, 0 ≤ b2i(by), ∀ bytes1. # bytes1 < #((by0 + []) + by ') → b2i(bytes1.first) = ~1 ∧ 0 ≤ b2i(bytes1.rest.first) → bits2bytes(sgn(bytes2bits(bytes1))) = bytes1 ∨ # bytes1 = 1 ∨ bytes1 = [] ⊦ i2b(bits2int(true ')) ' + i2b(bits2int(lastn(8, true ' + byte2bits(by)))) ' = by0 ' + by '

Rule argument

name: bits2bytes-base rotate: F subst: [bits] → [true ']

Additional information

Used simplifier rules: ⊦ # boolvar ' = 0 +1; Used terms: true '