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Proof step 34 from proof bytes2bytes-mone (previous step)

b2i(by0) = ~1, 0 ≤ b2i(by), ∀ bytes1. # bytes1 < #((by0 + []) + by ') → b2i(bytes1.first) = ~1 ∧ 0 ≤ b2i(bytes1.rest.first) → bits2bytes(sgn(bytes2bits(bytes1))) = bytes1 ∨ # bytes1 = 1 ∨ bytes1 = [] ⊦ i2b(~1) ' + i2b(bits2int(lastn(8, true ' + byte2bits(by)))) ' = by0 ' + by '

User applied rule insert equation

And obtained the following new goals

Proof step 35:
b2i(by0) = ~1, 0 ≤ b2i(by), ∀ bytes1. # bytes1 < #((by0 + []) + by ') → b2i(bytes1.first) = b2i(by0) ∧ 0 ≤ b2i(bytes1.rest.first) → bits2bytes(sgn(bytes2bits(bytes1))) = bytes1 ∨ # bytes1 = 1 ∨ bytes1 = [] ⊦ i2b(b2i(by0)) ' + i2b(bits2int(lastn(8, true ' + byte2bits(by)))) ' = by0 ' + by '

Rule argument

pos: left 1 flags: rotate

Proof step 34 from proof bytes2bytes-mone (previous step)

User applied rule insert equation

And obtained the following new goals

Rule argument

Additional information