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Proof step 7 from proof bytes2bytes-mone (previous step)

b2i(bytes.first) = ~1 ∧ 0 ≤ b2i(bytes.rest.first), ∀ bytes0. # bytes0 < # bytes → b2i(bytes0.first) = ~1 ∧ 0 ≤ b2i(bytes0.rest.first) → bits2bytes(sgn(bytes2bits(bytes0))) = bytes0 ∨ # bytes0 = 1 ∨ bytes0 = [] ⊦ bits2bytes(sgn(bytes2bits(bytes))) = bytes ∨ # bytes = 1 ∨ bytes = []

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 8:
b2i(bytes.first) = ~1, 0 ≤ b2i(bytes.rest.first), ∀ bytes0. # bytes0 < # bytes → b2i(bytes0.first) = ~1 ∧ 0 ≤ b2i(bytes0.rest.first) → bits2bytes(sgn(bytes2bits(bytes0))) = bytes0 ∨ # bytes0 = 1 ∨ bytes0 = [] ⊦ bytes = [], # bytes = 1, bits2bytes(sgn(bytes2bits(bytes))) = bytes

Proof step 7 from proof bytes2bytes-mone (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information