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Proof step 1 from proof bytes2bytes-other (conclusion)

bytes ≠ [], b2i(bytes.first) ≠ 0, b2i(bytes.first) ≠ ~1 ⊦ int2bytes(bytes2int(bytes)) = bytes

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
⊦ bytes = [], b2i(bytes.first) = 0, b2i(bytes.first) = ~1, int2bytes(bytes2int(bytes)) = bytes

Rule argument

Additional information