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Proof step 10 from proof bytes2bytes-other (previous step)

∀ bytes0. # bytes0 < # bytes → bytes2bits(bytes0) ≠ [] → bytes0 = [] ∨ b2i(bytes0.first) = 0 ∨ b2i(bytes0.first) = ~1 ∨ bits2bytes(sgn(bytes2bits(bytes0))) = bytes0 ⊦ bytes = [], b2i(bytes.first) = 0, b2i(bytes.first) = ~1, bits2bytes(sgn(bytes2bits(bytes))) = bytes

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 11:
⊦ bytes ≠ [] ↔ (∃ bytes0, by. bytes = bytes0 + by ')
Proof step 12:
∀ bytes0. # bytes0 < # bytes → bytes2bits(bytes0) ≠ [] → bytes0 = [] ∨ b2i(bytes0.first) = 0 ∨ b2i(bytes0.first) = ~1 ∨ bits2bytes(sgn(bytes2bits(bytes0))) = bytes0 ⊦ ∀ bytes0, by. bytes ≠ bytes0 + by ', b2i(bytes.first) = 0, b2i(bytes.first) = ~1, bits2bytes(sgn(bytes2bits(bytes))) = bytes

Rule argument

seq: ⊦ bytes ≠ [] ↔ (∃ bytes0, by. bytes = bytes0 + by ') subst: [bytes] → [bytes] rotate: F spec: list inst: bytelist name: lastdiv-rew

Additional information

Used terms: bytes