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Proof step 1 from proof bytes2bytes-zero (conclusion)

1 < # bytes, b2i(bytes.first) = 0, b2i(bytes.rest.first) < 0 ⊦ int2bytes(bytes2int(bytes)) = bytes

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
b2i(bytes.first) = 0, b2i(bytes.rest.first) < 0 ⊦ int2bytes(bytes2int(bytes)) = bytes, # bytes = 1, bytes = []

Rule argument

Additional information

Used simplifier rules: ⊦ j < i ∧ i ≤ 0 → j < 0; (forward)% ⊦ # bytes = 0 ↔ bytes = [];% ⊦ 1 < m ↔ ¬(m = 0 ∨ m = 1);