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Proof step 59 from proof bytes2bytes-zero (previous step)

b2i(by) = 0, b2i(by0) < 0, ∀ by0, by, bytes1. # bytes1 < #(bytes0 + by1 ') → b2i(by) = 0 ∧ b2i(by0) < 0 → bits2bytes(sgn(byte2bits(by) + byte2bits(by0) + bytes2bits(bytes1))) = by ' + by0 ' + bytes1 ⊦ bits2bytes(sgn((fillsgn(8, int2bits(b2i(by))) + byte2bits(by0) + bytes2bits(bytes0)) + byte2bits(by1))) = by ' + by0 ' + bytes0 + by1 ', (true ∈ fillsgn(8, int2bits(b2i(by))) ∨ true ∈ byte2bits(by0) ∨ true ∈ bytes2bits(bytes0)) ∧ (false ∈ fillsgn(8, int2bits(b2i(by))) ∨ false ∈ byte2bits(by0) ∨ false ∈ bytes2bits(bytes0))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: ⊦ boolvar ∈ boolvar0 ' ↔ boolvar ↔ boolvar0;%⊦ ¬ boolvar ∈ boolvar0 ' + bits ↔ ¬(boolvar ↔ boolvar0) ∧ ¬ boolvar ∈ bits;% ⊦ sgn(boolvar ' + boolvar ' + bits) = sgn(boolvar ' + bits);% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ bits + [] = bits;% ⊦ mklist(boolvar, 0) = [];%n ≠ 0 ⊦ mklist(false, (* n)) = false ' + mklist(false, n -1);% ⊦ 0 < n → fillsgn(n, boolvar ') = mklist(boolvar, n);% ⊦ int2bits(0) = false ';