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Proof step 9 from proof bytes2bytes-zero (previous step)

b2i(by) = 0, b2i(by0) < 0 ⊦ int2bytes(bits2int(byte2bits(by) + byte2bits(by0) + bytes2bits(bytes))) = by ' + by0 ' + bytes

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 10:
⊦ int2bytes(i) = bits2bytes(int2bits(i))
Proof step 11:
b2i(by) = 0, b2i(by0) < 0 ⊦ bits2bytes(int2bits(bits2int(byte2bits(by) + byte2bits(by0) + bytes2bits(bytes)))) = by ' + by0 ' + bytes

Rule argument

name: int2bytes rotate: F subst: [i] → [bits2int(byte2bits(by) + byte2bits(by0) + bytes2bits(bytes))]

Additional information

Used terms: bits2int(byte2bits(by) + byte2bits(by0) + bytes2bits(bytes))