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Proof step 1 from proof bytes2bytes (conclusion)

⊦ bytes ≠ [] → int2bytes(bytes2int(bytes)) = bits2bytes(sgn(bytes2bits(bytes)))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
⊦ bytes = [], int2bytes(bytes2int(bytes)) = bits2bytes(sgn(bytes2bits(bytes)))

Rule argument

Additional information