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Proof step 10 from proof bytes2int-011x-02 (previous step)

~1 = 2 ^ (8 * n→i(m)) + bytes2int(i2b(~2) ' + mklist(i2b(~1), m)) ⊦ ~256 = bytes2int(i2b(~2) ' + mklist(i2b(~1), m)) * 256 + 2 ^ (8 * (n→i(m) + 1))

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 11:
⊦ i * (j + j0) = i * j + i * j0
Proof step 12:
~1 = 2 ^ (8 * n→i(m)) + bytes2int(i2b(~2) ' + mklist(i2b(~1), m)) ⊦ ~256 = bytes2int(i2b(~2) ' + mklist(i2b(~1), m)) * 256 + 2 ^ (8 * n→i(m) + 8 * 1)

Rule argument

seq: ⊦ i * (j + j0) = i * j + i * j0 subst: [j0, j, i] → [1, n→i(m), 8] rotate: F spec: int-mult inst: name: dist-rsplit

Additional information

Used terms: 1, n→i(m), 8