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Proof step 7 from proof bytes2int-011x (previous step)

2 ^ (8 * n→i(m)) = bytes2int(i2b(0) ' + mklist(i2b(~1), m)) + 1 ⊦ 2 ^ (8 * (n→i(m) + 1)) = 1 + bytes2int(i2b(0) ' + mklist(i2b(~1), m) + i2b(~1) ')

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 8:
⊦ bytes ≠ [] → bytes2int(bytes + by ') = bytes2int(bytes) * 256 + band(b2i(by), 255)
Proof step 9:
i2b(0) ' + mklist(i2b(~1), m) ≠ [], 2 ^ (8 * n→i(m)) = bytes2int(i2b(0) ' + mklist(i2b(~1), m)) + 1 ⊦ 2 ^ (8 * (n→i(m) + 1)) = 1 + bytes2int(i2b(0) ' + mklist(i2b(~1), m)) * 256 + band(b2i(i2b(~1)), 255)

Rule argument

name: bytes2int-rec rotate: F subst: [by, bytes] → [i2b(~1), i2b(0) ' + mklist(i2b(~1), m)]

Additional information

Used simplifier rules: ⊦ ¬ bytes + bytes0 ≠ [] ↔ bytes = [] ∧ bytes0 = [];% ⊦ by ' ≠ [];% ⊦ (bytes + bytes0) + bytes1 = bytes + bytes0 + bytes1; Used terms: i2b(~1), i2b(0) ' + mklist(i2b(~1), m)