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Proof step 8 from proof bytes2int-100x-01 (previous step)

i2b(1) ' + mklist(i2b(0), m) ≠ [], bytes2int(i2b(1) ' + mklist(i2b(0), m)) = 2 ^ (8 * n→i(m)) ⊦ bytes2int(i2b(1) ' + mklist(i2b(0), m)) * 256 + band(b2i(i2b(0)), 255) = 2 ^ (8 * (n→i(m) + 1))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 9:
bytes2int(i2b(1) ' + mklist(i2b(0), m)) = 2 ^ (8 * n→i(m)) ⊦ 2 ^ (8 * n→i(m)) * 256 = 2 ^ (8 * (n→i(m) + 1))

Rule argument

Additional information

Used simplifier rules: ⊦ (bytes + bytes0) + bytes1 = bytes + bytes0 + bytes1;% ⊦ by ' + bytes ≠ [];% ⊦ i + j = j + i;% ⊦ i + j + i0 = (i + j) + i0;% ⊦ i + 0 = i;% ⊦ band(i, j) = band(j, i);% ⊦ band(i, band(i0, j)) = band(band(i, i0), j);% ⊦ 0 ≤ i → band(i, 255) = i % 256;% ⊦ b2i(i2b(0)) = 0;