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Proof step 3 from proof bytes2int-100x-02 (previous step)

2 ^ (8 * (1 + n→i(m)) - 1) + bytes2int(i2b(~128) ' + mklist(i2b(0), m)) = 0 ⊦ 2 ^ (8 * (1 + n→i(m +1)) - 1) + bytes2int(i2b(~128) ' + mklist(i2b(0), m +1)) = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
2 ^ (8 * (1 + n→i(m)) - 1) + bytes2int(i2b(~128) ' + mklist(i2b(0), m)) = 0 ⊦ bytes2int(i2b(~128) ' + mklist(i2b(0), m + 1)) + 2 ^ (8 * (2 + n→i(m)) - 1) = 0

Rule argument

Additional information

Used simplifier rules: ⊦ m + n = n + m;% ⊦ (m + n0) + n1 = m + n0 + n1;% ⊦ n→i(m + n) = n→i(m) + n→i(n);% ⊦ m +1 = m + 1;