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Proof step 2 from proof bytes2int-100x (previous step)

⊦ bytes2int(i2b(0) ' + i2b(~128) ' + mklist(i2b(0), 0)) = 2 ^ (8 * (1 + n→i(0)) - 1)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
⊦ bytes2int(i2b(0) ' + i2b(~128) ') = 128

Rule argument

Additional information

Used simplifier rules: ⊦ (bytes + bytes0) + bytes1 = bytes + bytes0 + bytes1;% ⊦ bytes + [] = bytes;% ⊦ mklist(by, 0) = [];