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Proof step 1 from proof bytes2int-1011x (conclusion)

⊦ bytes2int(i2b(~1) ' + i2b(127) ' + mklist(i2b(~1), n)) = ~(2 ^ (8 * (n→i(n) + 1) - 1) + 1)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
⊦ ~1 = 2 ^ (8 * (n→i(n) + 1) - 1) + bytes2int(i2b(~1) ' + i2b(127) ' + mklist(i2b(~1), n))

Rule argument

Additional information

Used simplifier rules: ⊦ i + j = j + i;% ⊦ i + j + i0 = (i + j) + i0;% ⊦ (* j) = i0 + (* j0) ↔ j - j0 = i0;% ⊦ ~ i = j ↔ i + j = 0;