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Proof step 13 from proof bytes2int-1011x (previous step)

~1 = 2 ^ (8 * (n→i(m) + 1) - 1) + bytes2int(i2b(~1) ' + i2b(127) ' + mklist(i2b(~1), m)) ⊦ ~256 = bytes2int(i2b(~1) ' + i2b(127) ' + mklist(i2b(~1), m)) * 256 + 2 ^ (8 * (2 + n→i(m)) - 1)

User applied rule cut formula

And obtained the following new goals

Proof step 14:
8 * (2 + n→i(m)) - 1 = 8 + (8 * (1 + n→i(m)) - 1), ~1 = 2 ^ (8 * (n→i(m) + 1) - 1) + bytes2int(i2b(~1) ' + i2b(127) ' + mklist(i2b(~1), m)) ⊦ ~256 = bytes2int(i2b(~1) ' + i2b(127) ' + mklist(i2b(~1), m)) * 256 + 2 ^ (8 * (2 + n→i(m)) - 1)

Rule argument

fma: 8 * (2 + n→i(m)) - 1 = 8 + (8 * (1 + n→i(m)) - 1)

Additional information

Used simplifier rules: ⊦ i + j = j + i;% ⊦ i + (j - i0) = i + j - i0;% ⊦ i * j + i = i * (j + 1);% ⊦ i * j * j0 = (i * j) * j0;% ⊦ i * j = j * i;% ⊦ i + j + i0 = (i + j) + i0;% ⊦ i - j = i0 ↔ i = i0 + j;% ⊦ i + (j - i) = j;% ⊦ 0 < i → (i * j = i * j0 ↔ j = j0); Used formulas: 8 * (2 + n→i(m)) - 1 = 8 + (8 * (1 + n→i(m)) - 1)