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Proof step 3 from proof bytes2int-1011x (previous step)

⊦ ~1 = 2 ^ (8 * (n→i(0) + 1) - 1) + bytes2int(i2b(~1) ' + i2b(127) ' + mklist(i2b(~1), 0))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
⊦ ~129 = bytes2int(i2b(~1) ' + i2b(127) ')

Rule argument

Additional information

Used simplifier rules: ⊦ i + j = j + i;% ⊦ i + j + i0 = (i + j) + i0;% ⊦ (* j) = i0 + (* j0) ↔ j - j0 = i0;% ⊦ (bytes + bytes0) + bytes1 = bytes + bytes0 + bytes1;% ⊦ bytes + [] = bytes;% ⊦ mklist(by, 0) = [];