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Proof step 26 from proof bytes2int-append (previous step)

bytes2bits(bytes).first ⊦ bitsinvert(bytes2bits(bytes)) + bitsinvert(bytes2bits(bytes0)) = [], (bits2uint(bitsinvert(bytes2bits(bytes)) + bitsinvert(bytes2bits(bytes0))) + 1) + band(bits2int(bytes2bits(bytes0)), 256 ^ n→i(# bytes0) - 1) = (bits2uint(bitsinvert(bytes2bits(bytes))) + 1) * 256 ^ n→i(# bytes0), bytes = [], bytes0 = [], bytes2bits(bytes) + bytes2bits(bytes0) = []

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

seq: ⊦ # bits0 ≠ 0 → bits2uint(bits + bits0) = bits2uint(bits) * 2 ^ n→i(# bits0) + bits2uint(bits0) subst: [bits0, bits] → [bitsinvert(bytes2bits(bytes0)), bitsinvert(bytes2bits(bytes))] rotate: F spec: int2bits inst: name: bits2uint-split

Additional information

Used terms: bitsinvert(bytes2bits(bytes0)), bitsinvert(bytes2bits(bytes))