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Proof step 3 from proof bytes2int-append (previous step)

bytes ≠ [], bytes0 ≠ [] ⊦ bits2int(bytes2bits(bytes + bytes0)) = bytes2int(bytes) * 256 ^ n→i(# bytes0) + band(bytes2int(bytes0), 256 ^ n→i(# bytes0) - 1)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
⊦ bytes2int(bytes) = bits2int(bytes2bits(bytes))
Proof step 5:
bytes ≠ [], bytes0 ≠ [] ⊦ bits2int(bytes2bits(bytes + bytes0)) = bits2int(bytes2bits(bytes)) * 256 ^ n→i(# bytes0) + band(bytes2int(bytes0), 256 ^ n→i(# bytes0) - 1)

Rule argument

name: bytes2int rotate: F subst: [bytes] → [bytes]

Additional information

Used terms: bytes