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Proof step 63 from proof bytes2int-append (previous step)

¬ (bytes2bits(bytes) + bytes2bits(bytes0)).first ∧ bytes2bits(bytes) + bytes2bits(bytes0) ≠ [] ⊦ bytes0 = [], bytes = [], bits2uint(bytes2bits(bytes) + bytes2bits(bytes0)) = bits2int(bytes2bits(bytes)) * 256 ^ n→i(# bytes0) + band(bits2int(bytes2bits(bytes0)), 256 ^ n→i(# bytes0) - 1)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 64:
⊦ bytes2bits(bytes) + bytes2bits(bytes0) = [], bits2uint(bytes2bits(bytes) + bytes2bits(bytes0)) = bits2int(bytes2bits(bytes)) * 256 ^ n→i(# bytes0) + band(bits2int(bytes2bits(bytes0)), 256 ^ n→i(# bytes0) - 1), bytes = [], bytes0 = [], (bytes2bits(bytes) + bytes2bits(bytes0)).first

Proof step 63 from proof bytes2int-append (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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