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Proof step 7 from proof bytes2int-append (previous step)

bytes ≠ [], bytes0 ≠ [] ⊦ bits2int(bytes2bits(bytes + bytes0)) = bits2int(bytes2bits(bytes)) * 256 ^ n→i(# bytes0) + band(bits2int(bytes2bits(bytes0)), 256 ^ n→i(# bytes0) - 1)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 8:
⊦ bytes0 = [], bytes = [], bits2int(bytes2bits(bytes) + bytes2bits(bytes0)) = bits2int(bytes2bits(bytes)) * 256 ^ n→i(# bytes0) + band(bits2int(bytes2bits(bytes0)), 256 ^ n→i(# bytes0) - 1)

Rule argument

Additional information

Used simplifier rules: bytes2bits-append: ⊦ bytes2bits(bytes + bytes0) = bytes2bits(bytes) + bytes2bits(bytes0);% ⊦ (bytes + bytes0) + bytes1 = bytes + bytes0 + bytes1;