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Proof step 70 from proof bytes2int-append (previous step)

⊦ bytes2bits(bytes) + bytes2bits(bytes0) = [], bits2uint(bytes2bits(bytes) + bytes2bits(bytes0)) = bits2uint(bytes2bits(bytes)) * 256 ^ n→i(# bytes0) + band(bits2int(bytes2bits(bytes0)), 256 ^ n→i(# bytes0) - 1), bytes = [], bytes0 = [], bytes2bits(bytes).first

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 71:
⊦ # bits0 ≠ 0 → bits2uint(bits + bits0) = bits2uint(bits) * 2 ^ n→i(# bits0) + bits2uint(bits0)
Proof step 72:
¬ # bytes2bits(bytes0) ≠ 0 ⊦ bytes2bits(bytes) + bytes2bits(bytes0) = [], bits2uint(bytes2bits(bytes) + bytes2bits(bytes0)) = bits2uint(bytes2bits(bytes)) * 256 ^ n→i(# bytes0) + band(bits2int(bytes2bits(bytes0)), 256 ^ n→i(# bytes0) - 1), bytes = [], bytes0 = [], bytes2bits(bytes).first
Proof step 75:
# bytes2bits(bytes0) ≠ 0 ⊦ bytes2bits(bytes) + bytes2bits(bytes0) = [], bits2uint(bytes2bits(bytes)) * 2 ^ n→i(# bytes2bits(bytes0)) + bits2uint(bytes2bits(bytes0)) = bits2uint(bytes2bits(bytes)) * 256 ^ n→i(# bytes0) + band(bits2int(bytes2bits(bytes0)), 256 ^ n→i(# bytes0) - 1), bytes = [], bytes0 = [], bytes2bits(bytes).first

Rule argument

seq: ⊦ # bits0 ≠ 0 → bits2uint(bits + bits0) = bits2uint(bits) * 2 ^ n→i(# bits0) + bits2uint(bits0) subst: [bits0, bits] → [bytes2bits(bytes0), bytes2bits(bytes)] rotate: F spec: int2bits inst: name: bits2uint-split

Additional information

Used terms: bytes2bits(bytes0), bytes2bits(bytes)