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Proof step 79 from proof bytes2int-append (previous step)

⊦ bytes = [], bytes0 = [], bytes2bits(bytes) + bytes2bits(bytes0) = [], bits2uint(bytes2bits(bytes0)) = band(bits2int(bytes2bits(bytes0)), 256 ^ n→i(# bytes0) - 1), bytes2bits(bytes).first

User applied rule cut formula

And obtained the following new goals

Proof step 80:
256 = 2 ^ 8 ⊦ bytes = [], bytes0 = [], bytes2bits(bytes) + bytes2bits(bytes0) = [], bits2uint(bytes2bits(bytes0)) = band(bits2int(bytes2bits(bytes0)), 256 ^ n→i(# bytes0) - 1), bytes2bits(bytes).first

Rule argument

fma: 256 = 2 ^ 8

Additional information

Used formulas: 256 = 2 ^ 8