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Proof step 19 from proof bytes2int-fillsgn-zero (previous step)

# bytes = m + 1, ∀ by. by ∈ bytes → b2i(by) = 0 ⊦ mklist(i2b(0), m + 1) = bytes, bytes = [], m = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 20:
⊦ bytes = bytes0 ↔ # bytes = # bytes0 ∧ (∀ n. n < # bytes → bytes[n] = bytes0[n])
Proof step 21:
# bytes = m + 1, ∀ by. by ∈ bytes → b2i(by) = 0 ⊦ # mklist(i2b(0), m + 1) = # bytes ∧ (∀ n. n < # mklist(i2b(0), m + 1) → mklist(i2b(0), m + 1)[n] = bytes[n]), bytes = [], m = 0

Rule argument

seq: ⊦ bytes = bytes0 ↔ # bytes = # bytes0 ∧ (∀ n. n < # bytes → bytes[n] = bytes0[n]) subst: [bytes0, bytes] → [bytes, mklist(i2b(0), m + 1)] rotate: F spec: list-del inst: bytelist name: extension

Additional information

Used terms: bytes, mklist(i2b(0), m + 1)