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Proof step 26 from proof bytes2int-fillsgn-zero (previous step)

# bytes = m + 1, b2i(bytes[n]) = 0, n ≤ m ⊦ bytes = [], m = 0, (mklist(i2b(0), m) + i2b(0) ')[n] = bytes[n]

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 27:
⊦ i2b(i) ≠ i2b(j) → i ≠ j
Proof step 28:
¬ i2b(b2i(bytes[n])) ≠ i2b(0), # bytes = m + 1, b2i(bytes[n]) = 0, n ≤ m ⊦ bytes = [], m = 0, (mklist(i2b(0), m) + i2b(0) ')[n] = bytes[n]

Rule argument

seq: ⊦ i2b(i) ≠ i2b(j) → i ≠ j subst: [j, i] → [0, b2i(bytes[n])] rotate: F spec: byte inst: name: i2b-noteq

Additional information

Used terms: 0, b2i(bytes[n])