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Proof step 4 from proof bytes2int-first-gez (previous step)

¬ ¬ 0 ≤ bytes2int(int2bytes(i).first + int2bytes(i).rest), 0 ≤ b2i(int2bytes(i).first), i < 0 ⊦

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 5:
⊦ bytes ≠ [] → bytes.first + bytes.rest = bytes

Rule argument

seq: ⊦ bytes ≠ [] → bytes.first + bytes.rest = bytes subst: [bytes] → [int2bytes(i)] rotate: F spec: list-data inst: bytelist name: fr-02

Additional information

Used simplifier rules: int2bytes-empty: ⊦ int2bytes(i) ≠ [];%int2bytes-empty: ⊦ int2bytes(i) ≠ [];%int2int: ⊦ bytes2int(int2bytes(i)) = i;% ⊦ i < j → (¬ ¬ j ≤ i ↔ false); Used terms: int2bytes(i)