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Proof step 2 from proof bytes2int-ge-zero (previous step)

⊦ 0 ≤ bytes2int(by ' + bytes) ↔ ¬ b2i(by) < 0

User applied rule case distinction

And obtained the following new goals

Proof step 3:
0 ≤ bytes2int(by ' + bytes) ⊦ ¬ b2i(by) < 0
Proof step 6:
¬ b2i(by) < 0 ⊦ 0 ≤ bytes2int(by ' + bytes)

Rule argument

pos: right 1

Additional information