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Proof step 4 from proof bytes2int-ge-zero (previous step)

0 ≤ bytes2int(by ' + bytes), b2i(by) < 0 ⊦

User applied rule insert lemma

And obtained the following new goals

Proof step 5:
⊦ bytes ≠ [] → (bytes2int(bytes) < 0 ↔ b2i(bytes.first) < 0)

Rule argument

name: bytes2int-neg subst: [bytes] → [by ' + bytes]

Additional information

Used simplifier rules: ⊦ ¬ bytes + bytes0 ≠ [] ↔ bytes = [] ∧ bytes0 = [];% ⊦ by ' ≠ [];% ⊦ (bytes + bytes0) + bytes1 = bytes + bytes0 + bytes1;% ⊦ ¬ i < j ↔ j ≤ i;% ⊦ i ≤ 0 ∧ 0 ≤ j → i ≤ j;% ⊦ (by ' + bytes).first = by;% ⊦ i < j → (¬ ¬ j ≤ i ↔ false);% ⊦ i ≤ j → (¬ ¬ j < i ↔ false); Used terms: by ' + bytes