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Proof step 3 from proof bytes2int-i2b (previous step)

bytes = bytes0 + by ' ⊦ bytes = [], i2b(bytes2int(bytes)) = by

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
⊦ i2b(bytes2int(bytes0 + by ')) = by

Rule argument

Additional information

Used simplifier rules: ⊦ (bytes + bytes0) + bytes1 = bytes + bytes0 + bytes1;% ⊦ bytes + by ' ≠ [];