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Proof step 1 from proof bytes2int-int2bytes-len-eq (conclusion)

⊦ # bytes = # int2bytes(bytes2int(bytes)) → bytes = int2bytes(bytes2int(bytes))

User applied rule induction

And obtained the following new goals

Proof step 2:
true, ∀ bytes0. # bytes0 < # bytes → true → # bytes0 = # int2bytes(bytes2int(bytes0)) → bytes0 = int2bytes(bytes2int(bytes0)) ⊦ # bytes = # int2bytes(bytes2int(bytes)) → bytes = int2bytes(bytes2int(bytes))

Rule argument

indvar: # bytes wfpred: <

Additional information

Used simplifier rules: <; (wellfounded) Used terms: # bytes