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Proof step 136 from proof bytes2int-int2bytes-len-eq (previous step)

1 = # bytes1, bytes2int(bytes1) * 256 + band(b2i(by), 255) = i + 256, ~129 < i, i < 0, ∀ bytes0. # bytes0 < #(bytes1 + by ') → true → # bytes0 = # int2bytes(bytes2int(bytes0)) → bytes0 = int2bytes(bytes2int(bytes0)) ⊦ bytes1 + by ' = i2b(0) ' + i2b(i) ', bytes1 = []

User applied rule flip equation

And obtained the following new goals

Rule argument

pos: left 1

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