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Proof step 154 from proof bytes2int-int2bytes-len-eq (previous step)

256 * b2i(by0) + band(b2i(by), 255) = i + 256, 0 ≤ b2i(by0), ~129 < i, i < 0, ∀ bytes0. # bytes0 < #((by0 + []) + by ') → true → # bytes0 = # int2bytes(bytes2int(bytes0)) → bytes0 = int2bytes(bytes2int(bytes0)) ⊦ by = i2b(0), by0 ' + by ' = i2b(0) ' + i2b(i) '

User applied rule cut formula

And obtained the following new goals

Proof step 155:
256 * (b2i(by0) - 1) + band(b2i(by), 255) = i, 256 * b2i(by0) + band(b2i(by), 255) = i + 256, 0 ≤ b2i(by0), ~129 < i, i < 0, ∀ bytes0. # bytes0 < #((by0 + []) + by ') → true → # bytes0 = # int2bytes(bytes2int(bytes0)) → bytes0 = int2bytes(bytes2int(bytes0)) ⊦ by = i2b(0), by0 ' + by ' = i2b(0) ' + i2b(i) '
Proof step 169:
256 * b2i(by0) + band(b2i(by), 255) = i + 256, 0 ≤ b2i(by0), ~129 < i, i < 0, ∀ bytes0. # bytes0 < #((by0 + []) + by ') → true → # bytes0 = # int2bytes(bytes2int(bytes0)) → bytes0 = int2bytes(bytes2int(bytes0)) ⊦ 256 * (b2i(by0) - 1) + band(b2i(by), 255) = i, by = i2b(0), by0 ' + by ' = i2b(0) ' + i2b(i) '

Rule argument

fma: 256 * (b2i(by0) - 1) + band(b2i(by), 255) = i

Additional information

Used formulas: 256 * (b2i(by0) - 1) + band(b2i(by), 255) = i