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Proof step 7 from proof bytes2int-int2bytes-len-eq (previous step)

1 = # int2bytes(bytes2int(bytes)), # bytes = 1, ∀ bytes0. # bytes0 < 1 → true → # bytes0 = # int2bytes(bytes2int(bytes0)) → bytes0 = int2bytes(bytes2int(bytes0)) ⊦ ∃ by. bytes = by ', bytes = int2bytes(bytes2int(bytes)), bytes = []

User applied rule exists right

And obtained the following new goals

Proof step 8:
1 = # int2bytes(bytes2int(bytes)), # bytes = 1, ∀ bytes0. # bytes0 < 1 → true → # bytes0 = # int2bytes(bytes2int(bytes0)) → bytes0 = int2bytes(bytes2int(bytes0)) ⊦ bytes = bytes.first ', ∃ by. bytes = by ', bytes = int2bytes(bytes2int(bytes)), bytes = []

Rule argument

pos: right 1 terms: bytes.first abort: F discard: F computed: F

Additional information

Used terms: bytes.first