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Proof step 96 from proof bytes2int-int2bytes-len-eq (previous step)

# bytes1 = # int2bytes(bytes2int(bytes1)), bytes2int(bytes1) < ~1, bytes2int(bytes1) < 0, ∀ bytes0. # bytes0 < #(bytes1 + i2b(0) ') → true → # bytes0 = # int2bytes(bytes2int(bytes0)) → bytes0 = int2bytes(bytes2int(bytes0)) ⊦ bytes1 = int2bytes(bytes2int(bytes1)), bytes1 = [], bytes2int(bytes1) * 256 = ~256

User applied rule apply induction

And closed the goal!

Rule argument

subst: [bytes0] → [bytes1]

Additional information

Used simplifier rules: ⊦ #(bytes + bytes0) = # bytes + # bytes0;% ⊦ # by ' = 0 +1;% ⊦ (bytes + bytes0) + bytes1 = bytes + bytes0 + bytes1;% ⊦ m < n + 1 ↔ ¬ n < m;% ⊦ ¬ n < n;% ⊦ (m + n0) + n1 = m + n0 + n1;% ⊦ m + n = n + m; Used terms: bytes1