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Proof step 99 from proof bytes2int-int2bytes-len-eq (previous step)

# bytes1 = 1, bytes2int(bytes1) * 256 + band(b2i(by), 255) = ~256, ∀ bytes0. # bytes0 < #(bytes1 + by ') → true → # bytes0 = # int2bytes(bytes2int(bytes0)) → bytes0 = int2bytes(bytes2int(bytes0)) ⊦ bytes1 + by ' = i2b(~1) ' + i2b(0) ', bytes1 = []

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 100:
⊦ # bytes = 1 ↔ bytes = bytes.first + []
Proof step 101:
bytes1 = bytes1.first + [], bytes2int(bytes1) * 256 + band(b2i(by), 255) = ~256, ∀ bytes0. # bytes0 < #(bytes1 + by ') → true → # bytes0 = # int2bytes(bytes2int(bytes0)) → bytes0 = int2bytes(bytes2int(bytes0)) ⊦ bytes1 + by ' = i2b(~1) ' + i2b(0) ', bytes1 = []

Rule argument

seq: ⊦ # bytes = 1 ↔ bytes = bytes.first + [] subst: [bytes] → [bytes1] rotate: F spec: list-data inst: bytelist name: lf-01

Additional information

Used terms: bytes1