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Proof step 10 from proof bytes2int-len-one-01 (previous step)

bytes2int(bytes0) * 256 < 128, 0 ≤ band(b2i(by), 255), bytes2int(bytes0) * 256 + band(b2i(by), 255) < 128, 0 ≤ bytes2int(bytes0) * 256 + band(b2i(by), 255) ⊦ bytes0.first = i2b(0), bytes0 = []

User applied rule cut formula

And obtained the following new goals

Proof step 11:
bytes2int(bytes0) = 0, bytes2int(bytes0) * 256 < 128, 0 ≤ band(b2i(by), 255), bytes2int(bytes0) * 256 + band(b2i(by), 255) < 128, 0 ≤ bytes2int(bytes0) * 256 + band(b2i(by), 255) ⊦ bytes0.first = i2b(0), bytes0 = []
Proof step 26:
bytes2int(bytes0) * 256 < 128, 0 ≤ band(b2i(by), 255), bytes2int(bytes0) * 256 + band(b2i(by), 255) < 128, 0 ≤ bytes2int(bytes0) * 256 + band(b2i(by), 255) ⊦ bytes2int(bytes0) = 0, bytes0.first = i2b(0), bytes0 = []

Rule argument

fma: bytes2int(bytes0) = 0

Additional information

Used formulas: bytes2int(bytes0) = 0